2sin^2(2x)-3cos(2x)=0

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Solution for 2sin^2(2x)-3cos(2x)=0 equation: 


Simplifying
2sin2(2x) + -3cos(2x) = 0

Remove parenthesis around (2x)
2in2s * 2x + -3cos(2x) = 0

Reorder the terms for easier multiplication:
2 * 2in2s * x + -3cos(2x) = 0

Multiply 2 * 2
4in2s * x + -3cos(2x) = 0

Multiply in2s * x
4in2sx + -3cos(2x) = 0

Remove parenthesis around (2x)
4in2sx + -3cos * 2x = 0

Reorder the terms for easier multiplication:
4in2sx + -3 * 2cos * x = 0

Multiply -3 * 2
4in2sx + -6cos * x = 0

Multiply cos * x
4in2sx + -6cosx = 0

Reorder the terms:
-6cosx + 4in2sx = 0

Solving
-6cosx + 4in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4in2sx' to each side of the equation.
-6cosx + 4in2sx + -4in2sx = 0 + -4in2sx

Combine like terms: 4in2sx + -4in2sx = 0
-6cosx + 0 = 0 + -4in2sx
-6cosx = 0 + -4in2sx
Remove the zero:
-6cosx = -4in2sx

Divide each side by '-6osx'.
c = 0.6666666667in2o-1

Simplifying
c = 0.6666666667in2o-1

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